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The isothermal atmosphere
As a first approximation, let us assume that the temperature of the
atmosphere is uniform. In such an /isothermal atmosphere/, we can
directly integrate the previous equation to give
\begin{displaymath} p = p_0 \exp\left(-\frac{z}{z_0}\right).
\end{displaymath} (327)
Here, $p_0$ is the pressure at ground level ($z=0$), which is generally
about 1 bar, or 1 atmosphere ($10^5$ N${\rm m}^{-2}$ in SI units). The
quantity
\begin{displaymath} z_0 = \frac{R\,T}{\mu \,g} \end{displaymath} (328)
is called the /isothermal scale-height/ of the atmosphere. At ground
level, the temperature is on average about 15$^\circ $ centigrade, which
is 288$^\circ $ kelvin on the absolute scale. The mean molecular weight
of air at sea level is 29 (/i.e./, the molecular weight of a gas made up
of 78% Nitrogen, 21% Oxygen, and 1% Argon). The acceleration due to
gravity is $9.81\,{\rm m}\,{\rm s}^{-2}$ at ground level. Also, the
ideal gas constant is $8.314$ joules/mole/degree. Putting all of this
information together, the isothermal scale-height of the atmosphere
comes out to be about $8.4$ kilometers.
We have discovered that in an isothermal atmosphere the pressure
decreases exponentially with increasing height. Since the temperature is
assumed to be constant, and $\rho\propto p/T$ [see Eq. (325
)], it follows that the density also decreases
exponentially with the same scale-height as the pressure. According to
Eq. (327 <#e6.68>), the pressure, or density, decreases by a factor 10
every $\ln \!10\, z_0$, or 19.3 kilometers, we move vertically upwards.
Clearly, the effective height of the atmosphere is pretty small compared
to the Earth's radius, which is about $6,400$ kilometers. In other
words, the atmosphere constitutes a very thin layer covering the surface
of the Earth. Incidentally, this justifies our neglect of the decrease
of $g$ with increasing altitude.
One of the highest points in the United States of America is the peak of
Mount Elbert in Colorado. This peak lies $14,432$ feet, or about $4.4$
kilometers, above sea level. At this altitude, our formula says that the
air pressure should be about $0.6$ atmospheres. Surprisingly enough,
after a few days acclimatization, people can survive quite comfortably
at this sort of pressure. In the highest inhabited regions of the Andes
and Tibet, the air pressure falls to about $0.5$ atmospheres. Humans can
just about survive at such pressures. However, people cannot survive for
any extended period in air pressures below half an atmosphere. This sets
an upper limit on the altitude of permanent human habitation, which is
about $19,000$ feet, or $5.8$ kilometers, above sea level. Incidentally,
this is also the maximum altitude at which a pilot can fly an
unpressurized aircraft without requiring additional Oxygen.
The highest point in the world is, of course, the peak of Mount Everest
in Nepal. This peak lies at an altitude of $29,028$ feet, or $8.85$
kilometers, above sea level, where we expect the air pressure to be a
mere $0.35$ atmospheres. This explains why Mount Everest was only
conquered after lightweight portable oxygen cylinders were invented.
Admittedly, some climbers have subsequently ascended Mount Everest
without the aid of additional oxygen, but this is a very foolhardy
venture, because above $19,000$ feet the climbers are slowly dying.
Commercial airliners fly at a cruising altitude of $32,000$ feet. At
this altitude, we expect the air pressure to be only $0.3$ atmospheres,
which explains why airline cabins are pressurized. In fact, the cabins
are only pressurized to $0.85$ atmospheres (which accounts for the
``popping'' of passangers ears during air travel). The reason for this
partial pressurization is quite simple. At $32,000$ feet, the pressure
difference between the air in the cabin and that outside is about half
an atmosphere. Clearly, the walls of the cabin must be strong enough to
support this pressure difference, which means that they must be of a
certain thickness, and, hence, the aircraft must be of a certain weight.
If the cabin were fully pressurized then the pressure difference at
cruising altitude would increase by about 30%, which means that the
cabin walls would have to be much thicker, and, hence, the aircraft
would have to be substantially heavier. So, a fully pressurized aircraft
would be more comfortable to fly in (because your ears would not
``pop''), but it would also be far less economical to operate.
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*Next:* The adiabatic atmosphere *Up:* Classical
thermodynamics *Previous:* Hydrostatic equilibrium of the
Richard Fitzpatrick 2006-02-02